Delaware County, OK Roof Snow Load - 10 psf
Delaware County, OK roof snow load, translated
A typical heated home in Delaware County is designed to carry 10 pounds per square foot of snow on its roof, per ASCE 7-22. 7 psf is what the ground-load formula alone gives; Delaware County's 10 psf low-slope minimum (§7.3.4) beats it, so that figure is the one that governs on flat and low-pitch roofs.
On a roof that means 22 in. of fresh snow, 8 in. once it packs down, or 2 in. of solid ice - three very different piles for the same load. This is a modest add-on to standard roof loading - ordinary residential construction carries it without extra bracing.
Delaware County at a glance
- Design roof snow load10 psf
- Ground snow load, ASCE 7 map10 psf
- National rank#1,799 of 2,758
- Oklahoma rank#39 of 77
- Population41,771
- Annual snowfall, NOAA normal5.5 in.
- FIPS40041
Where Delaware County ranks
#39 of 77 Oklahoma counties by design load, top 65% of 2,758 nationally - that's Delaware County's spot. That's 1 psf below Oklahoma's own county-average design load of 11 psf.
FIPS 40041, population 41,771, centered near 36.3934°N 94.8082°W. ASCE 7's underlying ground snow load here is 10 psf before the code's exposure and importance factors bring it to the 10 psf design figure above.
Delaware County: average annual snowfall
Delaware County sees about 5.5 in. of snow most winters, per the SPAVINAW, OK US station's 1991-2020 NOAA normal. See the density guide.
Read this before you use Delaware County's figure
The figure above assumes the case ASCE 7-22 treats as typical: a heated, ordinary-occupancy home on a partially exposed site. Change any of those - exposure, heating, roof pitch, occupancy category - and the real design number moves.
A building permit needs the number at your exact address, not the county average - the free ASCE 7 Hazard Tool returns that from your coordinates in about a minute and produces a PDF a plan reviewer will accept. (How this figure is calculated.)